{"id":102152,"date":"2026-09-08T08:41:12","date_gmt":"2026-09-08T00:41:12","guid":{"rendered":"https:\/\/www.wsisp.com\/helps\/102152.html"},"modified":"2026-09-08T08:41:12","modified_gmt":"2026-09-08T00:41:12","slug":"%e5%8d%8e%e4%b8%baod%e6%9c%ba%e8%af%95%e7%9c%9f%e9%a2%98-2026-9-6%e3%80%90%e5%b0%91%e5%84%bf%e7%88%ac%e5%b1%b1%e9%97%af%e5%85%b3%e7%a7%af%e5%88%86%e6%b8%b8%e6%88%8f%e3%80%91","status":"publish","type":"post","link":"https:\/\/www.wsisp.com\/helps\/102152.html","title":{"rendered":"\u534e\u4e3aOD\u673a\u8bd5\u771f\u9898 2026-9-6\u3010\u5c11\u513f\u722c\u5c71\u95ef\u5173\u79ef\u5206\u6e38\u620f\u3011"},"content":{"rendered":"

\u5c11\u513f\u722c\u5c71\u95ef\u5173\u79ef\u5206\u6e38\u620f(Java\/Py\/C\/C++\/Js\/Go)\u9898\u89e3<\/h2>\n

\u534e\u4e3aOD\u673a\u8bd5\u771f\u9898 \u65b0\u7cfb\u7edf \u534e\u4e3aOD\u4e0a\u673a\u8003\u8bd5\u771f\u9898\u65b0\u7cfb\u7edf 9\u67086\u53f7 100\u5206\u9898\u578b<\/p>\n

\u534e\u4e3aOD\u673a\u8bd5\u771f\u9898\u65b0\u7cfb\u7edf\u76ee\u5f55\u70b9\u51fb\u67e5\u770b: \u534e\u4e3aOD\u673a\u8bd5\u771f\u9898\u65b0\u7cfb\u7edf \u9898\u5e93\u76ee\u5f55｜\u673a\u8003\u9898\u5e93 + \u7b97\u6cd5\u8003\u70b9\u8be6\u89e3<\/p>\n

\u9898\u76ee\u5185\u5bb9<\/h2>\n

\u5c71\u8def\u4e00\u5171\u8bbe\u6709 <\/p>\n

n<\/p>\n

n<\/p>\n

<\/span><\/span>n<\/span><\/span><\/span><\/span><\/span> \u4e2a\u5173\u5361，\u6309 <\/p>\n

1<\/p>\n

\u223c<\/p>\n

n<\/p>\n

1 \\\\sim n<\/p>\n

<\/span><\/span>1<\/span><\/span>\u223c<\/span><\/span><\/span><\/span>n<\/span><\/span><\/span><\/span><\/span> \u987a\u5e8f\u6392\u5217\u3002\u5f53\u524d\u4f4d\u4e8e <\/p>\n

1<\/p>\n

1<\/p>\n

<\/span><\/span>1<\/span><\/span><\/span><\/span><\/span> \u53f7\u5173\u5361，\u5fc5\u987b\u6309\u7167\u5173\u5361\u4ece\u5c0f\u5230\u5927\u95ef\u5173，\u4e14\u5fc5\u987b\u5230\u8fbe\u6700\u540e\u7b2c <\/p>\n

n<\/p>\n

n<\/p>\n

<\/span><\/span>n<\/span><\/span><\/span><\/span><\/span> \u53f7\u5173\u5361\u624d\u7b97\u5bfb\u5b9d\u6210\u529f\u3002\u6bcf\u4e2a\u5173\u5361\u90fd\u6709\u5bf9\u5e94\u7684\u5b9d\u85cf\u5206\u503c(\u53ef\u80fd\u4e3a\u8d1f\u6570)，\u7ecf\u8fc7\u5f53\u524d\u5173\u5361\u5373\u53ef\u83b7\u5f97\u8be5\u5173\u5361\u5206\u503c，\u5206\u6570\u6301\u7eed\u7d2f\u52a0\u3002 \u79fb\u52a8\u89c4\u5219：<\/p>\n

  • \u4ece\u5f53\u524d\u5173\u5361，\u4e0b\u4e00\u6b21\u53ea\u80fd\u5728\u524d\u65b9 \n

    1<\/p>\n

    1<\/p>\n

    <\/span><\/span>1<\/span><\/span><\/span><\/span><\/span> \u5173\u6216\u8005 <\/p>\n

    2<\/p>\n

    2<\/p>\n

    <\/span><\/span>2<\/span><\/span><\/span><\/span><\/span> \u5173\u5904\u6253\u5361；<\/li>\n

  • \u9650\u5236\u89c4\u5219：\u4e0d\u80fd\u8fde\u7eed\u4e24\u6b21\u90fd\u4e00\u6b21\u6027\u8df3 \n

    2<\/p>\n

    2<\/p>\n

    <\/span><\/span>2<\/span><\/span><\/span><\/span><\/span> \u5173，\u8fdd\u53cd\u8be5\u89c4\u5219\u7684\u8def\u7ebf\u65e0\u6548； \u8bf7\u6c42\u51fa：\u6240\u6709\u5408\u6cd5\u8def\u7ebf\u4e2d，\u80fd\u591f\u6536\u96c6\u5230\u7684\u6700\u5927\u7d2f\u52a0\u603b\u5206\u3002<\/li>\n

    \u8f93\u5165\u63cf\u8ff0<\/h2>\n

    \u53c2\u65701：\u6574\u6570 <\/p>\n

    n<\/p>\n

    n<\/p>\n

    <\/span><\/span>n<\/span><\/span><\/span><\/span><\/span>，\u4ee3\u8868\u5173\u5361\u6570\u91cf \u53c2\u65702：\u6574\u6570\u6570\u7ec4，\u4f9d\u6b21\u8868\u793a\u7b2c <\/p>\n

    1<\/p>\n

    \u223c<\/p>\n

    n<\/p>\n

    1 \\\\sim n<\/p>\n

    <\/span><\/span>1<\/span><\/span>\u223c<\/span><\/span><\/span><\/span>n<\/span><\/span><\/span><\/span><\/span> \u5173\u7684\u5b9d\u85cf\u5206\u503c <\/p>\n

    1<\/p>\n

    \u2264<\/p>\n

    n<\/p>\n

    \u2264<\/p>\n

    20<\/p>\n

    1 \\\\leq n \\\\leq 20<\/p>\n

    <\/span><\/span>1<\/span><\/span>\u2264<\/span><\/span><\/span><\/span>n<\/span><\/span>\u2264<\/span><\/span><\/span><\/span>20<\/span><\/span><\/span><\/span><\/span> \u6bcf\u5173\u5206\u503c：<\/p>\n

    \u2212<\/p>\n

    999<\/p>\n

    \u2264<\/p>\n

    v<\/p>\n

    a<\/p>\n

    l<\/p>\n

    \u2264<\/p>\n

    999<\/p>\n

    -999 \\\\leq val \\\\leq 999<\/p>\n

    <\/span><\/span>\u2212<\/span>999<\/span><\/span>\u2264<\/span><\/span><\/span><\/span>v<\/span>a<\/span>l<\/span><\/span>\u2264<\/span><\/span><\/span><\/span>999<\/span><\/span><\/span><\/span><\/span><\/p>\n

    \u8f93\u51fa\u63cf\u8ff0<\/h2>\n

    \u8f93\u51fa\u4e00\u4e2a\u6574\u6570，\u4ee3\u8868\u5408\u6cd5\u8def\u7ebf\u7684\u6700\u5927\u7d2f\u52a0\u5f97\u5206\u3002<\/p>\n

    \u6837\u4f8b1<\/h2>\n

    \u8f93\u5165<\/p>\n

    5
    \n10 5 8 3 15<\/p>\n

    \u8f93\u51fa<\/p>\n

    41<\/p>\n

    \u8bf4\u660e<\/p>\n

      \n
    • \u5408\u6cd5\u8def\u7ebf\u793a\u4f8b：\n

      1<\/p>\n

      \u2192<\/p>\n

      2<\/p>\n

      \u2192<\/p>\n

      3<\/p>\n

      \u2192<\/p>\n

      4<\/p>\n

      \u2192<\/p>\n

      5<\/p>\n

      1 \\\\rightarrow 2 \\\\rightarrow 3 \\\\rightarrow 4 \\\\rightarrow 5<\/p>\n

      <\/span><\/span>1<\/span><\/span>\u2192<\/span><\/span><\/span><\/span>2<\/span><\/span>\u2192<\/span><\/span><\/span><\/span>3<\/span><\/span>\u2192<\/span><\/span><\/span><\/span>4<\/span><\/span>\u2192<\/span><\/span><\/span><\/span>5<\/span><\/span><\/span><\/span><\/span>，\u65e0\u8fde\u7eed\u8df3\u4e24\u5173，\u603b\u5206：<\/p>\n

      10<\/p>\n

      +<\/p>\n

      5<\/p>\n

      +<\/p>\n

      8<\/p>\n

      +<\/p>\n

      3<\/p>\n

      +<\/p>\n

      15<\/p>\n

      =<\/p>\n

      41<\/p>\n

      10+5+8+3+15 = 41<\/p>\n

      <\/span><\/span>10<\/span><\/span>+<\/span><\/span><\/span><\/span>5<\/span><\/span>+<\/span><\/span><\/span><\/span>8<\/span><\/span>+<\/span><\/span><\/span><\/span>3<\/span><\/span>+<\/span><\/span><\/span><\/span>15<\/span><\/span>=<\/span><\/span><\/span><\/span>41<\/span><\/span><\/span><\/span><\/span><\/li>\n

    • \u8def\u7ebf \n

      1<\/p>\n

      \u2192<\/p>\n

      3<\/p>\n

      \u2192<\/p>\n

      5<\/p>\n

      1 \\\\rightarrow 3 \\\\rightarrow 5<\/p>\n

      <\/span><\/span>1<\/span><\/span>\u2192<\/span><\/span><\/span><\/span>3<\/span><\/span>\u2192<\/span><\/span><\/span><\/span>5<\/span><\/span><\/span><\/span><\/span> \u8fde\u7eed\u4e24\u6b21\u8df3 <\/p>\n

      2<\/p>\n

      2<\/p>\n

      <\/span><\/span>2<\/span><\/span><\/span><\/span><\/span> \u5173，\u8fdd\u89c4，\u4e0d\u8ba1\u5165\u7edf\u8ba1\u3002<\/li>\n<\/ul>\n

      \u6837\u4f8b2<\/h2>\n

      \u8f93\u5165<\/p>\n

      4
      \n10 1 1 100<\/p>\n

      \u8f93\u51fa<\/p>\n

      112<\/p>\n

      \u8bf4\u660e<\/p>\n

        \n
      • \u8def\u7ebf \n

        1<\/p>\n

        \u2192<\/p>\n

        2<\/p>\n

        \u2192<\/p>\n

        3<\/p>\n

        \u2192<\/p>\n

        4<\/p>\n

        1 \\\\rightarrow 2 \\\\rightarrow 3 \\\\rightarrow 4<\/p>\n

        <\/span><\/span>1<\/span><\/span>\u2192<\/span><\/span><\/span><\/span>2<\/span><\/span>\u2192<\/span><\/span><\/span><\/span>3<\/span><\/span>\u2192<\/span><\/span><\/span><\/span>4<\/span><\/span><\/span><\/span><\/span> <\/p>\n

        (<\/p>\n

        1<\/p>\n

        ,<\/p>\n

        1<\/p>\n

        ,<\/p>\n

        1<\/p>\n

        )<\/p>\n

        (1,1,1)<\/p>\n

        <\/span><\/span>(<\/span>1<\/span>,<\/span><\/span>1<\/span>,<\/span><\/span>1<\/span>)<\/span><\/span><\/span><\/span><\/span>: <\/p>\n

        10<\/p>\n

        +<\/p>\n

        1<\/p>\n

        +<\/p>\n

        1<\/p>\n

        +<\/p>\n

        100<\/p>\n

        =<\/p>\n

        112<\/p>\n

        10+1+1+100=112<\/p>\n

        <\/span><\/span>10<\/span><\/span>+<\/span><\/span><\/span><\/span>1<\/span><\/span>+<\/span><\/span><\/span><\/span>1<\/span><\/span>+<\/span><\/span><\/span><\/span>100<\/span><\/span>=<\/span><\/span><\/span><\/span>112<\/span><\/span><\/span><\/span><\/span><\/li>\n

      • \u8def\u7ebf \n

        1<\/p>\n

        \u2192<\/p>\n

        3<\/p>\n

        \u2192<\/p>\n

        4<\/p>\n

        1 \\\\rightarrow 3 \\\\rightarrow 4<\/p>\n

        <\/span><\/span>1<\/span><\/span>\u2192<\/span><\/span><\/span><\/span>3<\/span><\/span>\u2192<\/span><\/span><\/span><\/span>4<\/span><\/span><\/span><\/span><\/span> <\/p>\n

        (<\/p>\n

        2<\/p>\n

        ,<\/p>\n

        1<\/p>\n

        )<\/p>\n

        (2,1)<\/p>\n

        <\/span><\/span>(<\/span>2<\/span>,<\/span><\/span>1<\/span>)<\/span><\/span><\/span><\/span><\/span>: <\/p>\n

        10<\/p>\n

        +<\/p>\n

        1<\/p>\n

        +<\/p>\n

        100<\/p>\n

        =<\/p>\n

        111<\/p>\n

        10+1+100=111<\/p>\n

        <\/span><\/span>10<\/span><\/span>+<\/span><\/span><\/span><\/span>1<\/span><\/span>+<\/span><\/span><\/span><\/span>100<\/span><\/span>=<\/span><\/span><\/span><\/span>111<\/span><\/span><\/span><\/span><\/span><\/li>\n

      • \u8def\u7ebf \n

        1<\/p>\n

        \u2192<\/p>\n

        2<\/p>\n

        \u2192<\/p>\n

        4<\/p>\n

        1 \\\\rightarrow 2 \\\\rightarrow 4<\/p>\n

        <\/span><\/span>1<\/span><\/span>\u2192<\/span><\/span><\/span><\/span>2<\/span><\/span>\u2192<\/span><\/span><\/span><\/span>4<\/span><\/span><\/span><\/span><\/span> <\/p>\n

        (<\/p>\n

        1<\/p>\n

        ,<\/p>\n

        2<\/p>\n

        )<\/p>\n

        (1,2)<\/p>\n

        <\/span><\/span>(<\/span>1<\/span>,<\/span><\/span>2<\/span>)<\/span><\/span><\/span><\/span><\/span>: <\/p>\n

        10<\/p>\n

        +<\/p>\n

        1<\/p>\n

        +<\/p>\n

        100<\/p>\n

        =<\/p>\n

        111<\/p>\n

        10+1+100=111<\/p>\n

        <\/span><\/span>10<\/span><\/span>+<\/span><\/span><\/span><\/span>1<\/span><\/span>+<\/span><\/span><\/span><\/span>100<\/span><\/span>=<\/span><\/span><\/span><\/span>111<\/span><\/span><\/span><\/span><\/span><\/li>\n

      • \u6700\u5927\u503c \n

        112<\/p>\n

        112<\/p>\n

        <\/span><\/span>112<\/span><\/span><\/span><\/span><\/span>\u3002<\/li>\n<\/ul>\n

        \u9898\u89e3<\/h2>\n

        \u601d\u8def：\u52a8\u6001\u89c4\u5212<\/p>\n

      • \u5b9a\u4e49dp[][2]\u6570\u7ec4，\u5176\u4e2ddp[i][0]\u5230\u8fbe i，\u6700\u540e\u4e00\u6b65\u8df3 1 \u683c\u80fd\u53d6\u5230\u7684\u6700\u5927\u603b\u5206，\u5176\u4e2ddp[i][1]\u5230\u8fbe i，\u6700\u540e\u4e00\u6b65\u8df3 2\u683c\u80fd\u53d6\u5230\u7684\u6700\u5927\u603b\u5206<\/li>\n
      • \u5f53\u524d\u5230\u8fbe\u4f4d\u7f6ei，\u8fdb\u884c\u72b6\u6001\u8fc7\u7a0b\u4e3a:\n
          \n
        • \u53ea\u8df3\u4e00\u6b65\u5230\u8fbe，i-1 -> i, \u53ef\u4ee5\u4ece\u4e0a\u4e2a\u4f4d\u7f6e\u8df3\u4e00\u6b21\u548c\u8df3\u4e24\u6b21\u8f6c\u79fb，\u6240\u4ee5dp[i][0] = max(dp[i-1][0], dp[i-1][1]) + a[i]<\/li>\n
        • \u8df3\u4e24\u6b65\u5230\u8fbe，i-2 -> i, \u53ea\u80fd\u4ecei-2\u4f4d\u7f6e\u8df3\u4e00\u6b21\u8f6c\u79fb，\u6240\u4ee5 dp[i][1] = dp[i-2][0] + a[i];<\/li>\n<\/ul>\n<\/li>\n
        • \u6700\u7ec8\u80fd\u53d6\u5230\u7684\u6700\u5927\u603b\u5206\u4e3amax(dp[n-1][0], dp[n-1][1])<\/li>\n

          c++<\/h3>\n

          #<\/span>include<\/span> <bits\/stdc++.h><\/span><\/span>
          \n#<\/span>include<\/span> <vector><\/span><\/span>
          \nusing<\/span> namespace<\/span> std;<\/span><\/p>\n

          int<\/span> solve<\/span>(<\/span>int<\/span> n,<\/span> vector<<\/span>int<\/span>><\/span>&<\/span> a)<\/span> {<\/span>
          \n \/\/ dp[i][0] \u4e0a\u4e00\u6b65\u8df3\u4e00\u6b65\u6700\u5927\u503c dp[i][1]\u4e0a\u4e00\u6b65\u8df3\u4e24\u6b65\u6700\u5927\u503c<\/span>
          \n vector<<\/span>vector<<\/span>int<\/span>>><\/span> dp<\/span>(<\/span>n,<\/span> vector<\/span><<\/span>int<\/span>><\/span><\/span><\/span>(<\/span>2<\/span>,<\/span> 0<\/span>)<\/span>)<\/span>;<\/span>
          \n dp[<\/span>0<\/span>]<\/span>[<\/span>0<\/span>]<\/span> =<\/span> a[<\/span>0<\/span>]<\/span>;<\/span>
          \n dp[<\/span>0<\/span>]<\/span>[<\/span>1<\/span>]<\/span> =<\/span> a[<\/span>0<\/span>]<\/span>;<\/span>
          \n for<\/span> (<\/span>int<\/span> i =<\/span> 1<\/span>;<\/span> i <<\/span> n;<\/span> i++<\/span>)<\/span> {<\/span>
          \n dp[<\/span>i]<\/span>[<\/span>0<\/span>]<\/span> =<\/span> max<\/span>(<\/span>dp[<\/span>i–<\/span>1<\/span>]<\/span>[<\/span>0<\/span>]<\/span>,<\/span> dp[<\/span>i–<\/span>1<\/span>]<\/span>[<\/span>1<\/span>]<\/span>)<\/span> +<\/span> a[<\/span>i]<\/span>;<\/span>
          \n if<\/span> (<\/span>i ><\/span> 1<\/span>)<\/span> {<\/span>
          \n dp[<\/span>i]<\/span>[<\/span>1<\/span>]<\/span> =<\/span> dp[<\/span>i–<\/span>2<\/span>]<\/span>[<\/span>0<\/span>]<\/span> +<\/span> a[<\/span>i]<\/span>;<\/span>
          \n }<\/span>
          \n }<\/span>
          \n return<\/span> max<\/span>(<\/span>dp[<\/span>n–<\/span>1<\/span>]<\/span>[<\/span>0<\/span>]<\/span>,<\/span> dp[<\/span>n–<\/span>1<\/span>]<\/span>[<\/span>1<\/span>]<\/span>)<\/span>;<\/span>
          \n}<\/span><\/p>\n

          int<\/span> main<\/span>(<\/span>)<\/span> {<\/span>
          \n int<\/span> n;<\/span>
          \n cin >><\/span> n;<\/span>
          \n vector<<\/span>int<\/span>><\/span> a<\/span>(<\/span>n)<\/span>;<\/span>
          \n for<\/span> (<\/span>int<\/span> i =<\/span> 0<\/span>;<\/span> i <<\/span> n;<\/span> i++<\/span>)<\/span> {<\/span>
          \n cin >><\/span> a[<\/span>i]<\/span>;<\/span>
          \n }<\/span>
          \n cout <<<\/span> solve<\/span>(<\/span>n,<\/span> a)<\/span>;<\/span>
          \n return<\/span> 0<\/span>;<\/span>
          \n}<\/span><\/p>\n

          Java<\/h3>\n

          #include <<\/span>bits\/<\/span>stdc++<\/span>.<\/span>h><\/span>
          \n#include <<\/span>vector><\/span><\/span>
          \nusing namespace std;<\/span><\/p>\n

          int<\/span> solve<\/span>(<\/span>int<\/span> n,<\/span> vector<<\/span>int<\/span>><\/span><\/span>&<\/span> a)<\/span> {<\/span>
          \n \/\/ dp[i][0] \u4e0a\u4e00\u6b65\u8df3\u4e00\u6b65\u6700\u5927\u503c dp[i][1]\u4e0a\u4e00\u6b65\u8df3\u4e24\u6b65\u6700\u5927\u503c<\/span>
          \n vector<<\/span>vector<<\/span>int<\/span>><\/span>><\/span><\/span> dp<\/span>(<\/span>n,<\/span> vector<<\/span>int<\/span>><\/span><\/span>(<\/span>2<\/span>,<\/span> 0<\/span>)<\/span>)<\/span>;<\/span>
          \n dp[<\/span>0<\/span>]<\/span>[<\/span>0<\/span>]<\/span> =<\/span> a[<\/span>0<\/span>]<\/span>;<\/span>
          \n dp[<\/span>0<\/span>]<\/span>[<\/span>1<\/span>]<\/span> =<\/span> a[<\/span>0<\/span>]<\/span>;<\/span>
          \n for<\/span> (<\/span>int<\/span> i =<\/span> 1<\/span>;<\/span> i <<\/span> n;<\/span> i++<\/span>)<\/span> {<\/span>
          \n dp[<\/span>i]<\/span>[<\/span>0<\/span>]<\/span> =<\/span> max<\/span>(<\/span>dp[<\/span>i–<\/span>1<\/span>]<\/span>[<\/span>0<\/span>]<\/span>,<\/span> dp[<\/span>i–<\/span>1<\/span>]<\/span>[<\/span>1<\/span>]<\/span>)<\/span> +<\/span> a[<\/span>i]<\/span>;<\/span>
          \n if<\/span> (<\/span>i ><\/span> 1<\/span>)<\/span> {<\/span>
          \n dp[<\/span>i]<\/span>[<\/span>1<\/span>]<\/span> =<\/span> dp[<\/span>i–<\/span>2<\/span>]<\/span>[<\/span>0<\/span>]<\/span> +<\/span> a[<\/span>i]<\/span>;<\/span>
          \n }<\/span>
          \n }<\/span>
          \n return<\/span> max<\/span>(<\/span>dp[<\/span>n–<\/span>1<\/span>]<\/span>[<\/span>0<\/span>]<\/span>,<\/span> dp[<\/span>n–<\/span>1<\/span>]<\/span>[<\/span>1<\/span>]<\/span>)<\/span>;<\/span>
          \n}<\/span><\/p>\n

          int<\/span> main<\/span>(<\/span>)<\/span> {<\/span>
          \n int<\/span> n;<\/span>
          \n cin >><\/span> n;<\/span>
          \n vector<<\/span>int<\/span>><\/span><\/span> a<\/span>(<\/span>n)<\/span>;<\/span>
          \n for<\/span> (<\/span>int<\/span> i =<\/span> 0<\/span>;<\/span> i <<\/span> n;<\/span> i++<\/span>)<\/span> {<\/span>
          \n cin >><\/span> a[<\/span>i]<\/span>;<\/span>
          \n }<\/span>
          \n cout <<<\/span> solve<\/span>(<\/span>n,<\/span> a)<\/span>;<\/span>
          \n return<\/span> 0<\/span>;<\/span>
          \n}<\/span><\/p>\n

          Python<\/h3>\n

          import<\/span> sys<\/p>\n

          def<\/span> solve<\/span>(<\/span>n,<\/span> a)<\/span>:<\/span>
          \n # dp[i][0] \u4e0a\u4e00\u6b65\u8df3\u4e00\u6b65\u6700\u5927\u503c dp[i][1]\u4e0a\u4e00\u6b65\u8df3\u4e24\u6b65\u6700\u5927\u503c<\/span>
          \n dp =<\/span> [<\/span>[<\/span>0<\/span>,<\/span> 0<\/span>]<\/span> for<\/span> _ in<\/span> range<\/span>(<\/span>n)<\/span>]<\/span><\/p>\n

          dp[<\/span>0<\/span>]<\/span>[<\/span>0<\/span>]<\/span> =<\/span> a[<\/span>0<\/span>]<\/span>
          \n dp[<\/span>0<\/span>]<\/span>[<\/span>1<\/span>]<\/span> =<\/span> a[<\/span>0<\/span>]<\/span><\/p>\n

          for<\/span> i in<\/span> range<\/span>(<\/span>1<\/span>,<\/span> n)<\/span>:<\/span>
          \n dp[<\/span>i]<\/span>[<\/span>0<\/span>]<\/span> =<\/span> max<\/span>(<\/span>dp[<\/span>i –<\/span> 1<\/span>]<\/span>[<\/span>0<\/span>]<\/span>,<\/span> dp[<\/span>i –<\/span> 1<\/span>]<\/span>[<\/span>1<\/span>]<\/span>)<\/span> +<\/span> a[<\/span>i]<\/span><\/p>\n

          if<\/span> i ><\/span> 1<\/span>:<\/span>
          \n dp[<\/span>i]<\/span>[<\/span>1<\/span>]<\/span> =<\/span> dp[<\/span>i –<\/span> 2<\/span>]<\/span>[<\/span>0<\/span>]<\/span> +<\/span> a[<\/span>i]<\/span><\/p>\n

          return<\/span> max<\/span>(<\/span>dp[<\/span>n –<\/span> 1<\/span>]<\/span>[<\/span>0<\/span>]<\/span>,<\/span> dp[<\/span>n –<\/span> 1<\/span>]<\/span>[<\/span>1<\/span>]<\/span>)<\/span><\/p>\n

          data =<\/span> list<\/span>(<\/span>map<\/span>(<\/span>int<\/span>,<\/span> sys.<\/span>stdin.<\/span>read(<\/span>)<\/span>.<\/span>split(<\/span>)<\/span>)<\/span>)<\/span><\/p>\n

          n =<\/span> data[<\/span>0<\/span>]<\/span>
          \na =<\/span> data[<\/span>1<\/span>:<\/span>n +<\/span> 1<\/span>]<\/span><\/p>\n

          print<\/span>(<\/span>solve(<\/span>n,<\/span> a)<\/span>)<\/span><\/p>\n

          JavaScript<\/h3>\n

          const<\/span> readline =<\/span> require<\/span>(<\/span>'readline'<\/span>)<\/span>;<\/span><\/p>\n

          const<\/span> rl =<\/span> readline.<\/span>createInterface<\/span>(<\/span>{<\/span>
          \n input<\/span>:<\/span> process.<\/span>stdin,<\/span>
          \n output<\/span>:<\/span> process.<\/span>stdout
          \n}<\/span>)<\/span>;<\/span><\/p>\n

          const<\/span> input =<\/span> [<\/span>]<\/span>;<\/span><\/p>\n

          rl.<\/span>on<\/span>(<\/span>'line'<\/span>,<\/span> line<\/span> =><\/span> {<\/span>
          \n input.<\/span>push<\/span>(<\/span>line)<\/span>;<\/span>
          \n}<\/span>)<\/span>;<\/span><\/p>\n

          rl.<\/span>on<\/span>(<\/span>'close'<\/span>,<\/span> (<\/span>)<\/span> =><\/span> {<\/span>
          \n const<\/span> data =<\/span> input.<\/span>join<\/span>(<\/span>' '<\/span>)<\/span>.<\/span>trim<\/span>(<\/span>)<\/span>.<\/span>split<\/span>(<\/span>\/<\/span>\\\\s+<\/span>\/<\/span><\/span>)<\/span>.<\/span>map<\/span>(<\/span>Number)<\/span>;<\/span><\/p>\n

          const<\/span> n =<\/span> data[<\/span>0<\/span>]<\/span>;<\/span>
          \n const<\/span> a =<\/span> data.<\/span>slice<\/span>(<\/span>1<\/span>,<\/span> n +<\/span> 1<\/span>)<\/span>;<\/span><\/p>\n

          console.<\/span>log<\/span>(<\/span>solve<\/span>(<\/span>n,<\/span> a)<\/span>)<\/span>;<\/span>
          \n}<\/span>)<\/span>;<\/span><\/p>\n

          function<\/span> solve<\/span>(<\/span>n,<\/span> a<\/span>)<\/span> {<\/span>
          \n \/\/ dp[i][0] \u4e0a\u4e00\u6b65\u8df3\u4e00\u6b65\u6700\u5927\u503c dp[i][1]\u4e0a\u4e00\u6b65\u8df3\u4e24\u6b65\u6700\u5927\u503c<\/span>
          \n const<\/span> dp =<\/span> Array.<\/span>from<\/span>(<\/span>{<\/span> length<\/span>:<\/span> n }<\/span>,<\/span> (<\/span>)<\/span> =><\/span> [<\/span>0<\/span>,<\/span> 0<\/span>]<\/span>)<\/span>;<\/span><\/p>\n

          dp[<\/span>0<\/span>]<\/span>[<\/span>0<\/span>]<\/span> =<\/span> a[<\/span>0<\/span>]<\/span>;<\/span>
          \n dp[<\/span>0<\/span>]<\/span>[<\/span>1<\/span>]<\/span> =<\/span> a[<\/span>0<\/span>]<\/span>;<\/span><\/p>\n

          for<\/span> (<\/span>let<\/span> i =<\/span> 1<\/span>;<\/span> i <<\/span> n;<\/span> i++<\/span>)<\/span> {<\/span>
          \n dp[<\/span>i]<\/span>[<\/span>0<\/span>]<\/span> =<\/span> Math.<\/span>max<\/span>(<\/span>dp[<\/span>i –<\/span> 1<\/span>]<\/span>[<\/span>0<\/span>]<\/span>,<\/span> dp[<\/span>i –<\/span> 1<\/span>]<\/span>[<\/span>1<\/span>]<\/span>)<\/span> +<\/span> a[<\/span>i]<\/span>;<\/span><\/p>\n

          if<\/span> (<\/span>i ><\/span> 1<\/span>)<\/span> {<\/span>
          \n dp[<\/span>i]<\/span>[<\/span>1<\/span>]<\/span> =<\/span> dp[<\/span>i –<\/span> 2<\/span>]<\/span>[<\/span>0<\/span>]<\/span> +<\/span> a[<\/span>i]<\/span>;<\/span>
          \n }<\/span>
          \n }<\/span><\/p>\n

          return<\/span> Math.<\/span>max<\/span>(<\/span>dp[<\/span>n –<\/span> 1<\/span>]<\/span>[<\/span>0<\/span>]<\/span>,<\/span> dp[<\/span>n –<\/span> 1<\/span>]<\/span>[<\/span>1<\/span>]<\/span>)<\/span>;<\/span>
          \n}<\/span><\/p>\n

          Go<\/h3>\n

          package<\/span> main<\/p>\n

          import<\/span> (<\/span>
          \n"bufio"<\/span>
          \n"fmt"<\/span>
          \n"os"<\/span>
          \n)<\/span><\/p>\n

          \/\/ \u89e3\u51b3\u95ee\u9898<\/span>
          \nfunc<\/span> solve<\/span>(<\/span>n int<\/span>,<\/span> a [<\/span>]<\/span>int<\/span>)<\/span> int<\/span> {<\/span>
          \n\/\/ dp[i][0] \u4e0a\u4e00\u6b65\u8df3\u4e00\u6b65\u6700\u5927\u503c dp[i][1]\u4e0a\u4e00\u6b65\u8df3\u4e24\u6b65\u6700\u5927\u503c<\/span>
          \ndp :=<\/span> make<\/span>(<\/span>[<\/span>]<\/span>[<\/span>2<\/span>]<\/span>int<\/span>,<\/span> n)<\/span><\/p>\n

          dp[<\/span>0<\/span>]<\/span>[<\/span>0<\/span>]<\/span> =<\/span> a[<\/span>0<\/span>]<\/span>
          \ndp[<\/span>0<\/span>]<\/span>[<\/span>1<\/span>]<\/span> =<\/span> a[<\/span>0<\/span>]<\/span><\/p>\n

          for<\/span> i :=<\/span> 1<\/span>;<\/span> i <<\/span> n;<\/span> i++<\/span> {<\/span>
          \nif<\/span> dp[<\/span>i–<\/span>1<\/span>]<\/span>[<\/span>0<\/span>]<\/span> ><\/span> dp[<\/span>i–<\/span>1<\/span>]<\/span>[<\/span>1<\/span>]<\/span> {<\/span>
          \ndp[<\/span>i]<\/span>[<\/span>0<\/span>]<\/span> =<\/span> dp[<\/span>i–<\/span>1<\/span>]<\/span>[<\/span>0<\/span>]<\/span> +<\/span> a[<\/span>i]<\/span>
          \n}<\/span> else<\/span> {<\/span>
          \ndp[<\/span>i]<\/span>[<\/span>0<\/span>]<\/span> =<\/span> dp[<\/span>i–<\/span>1<\/span>]<\/span>[<\/span>1<\/span>]<\/span> +<\/span> a[<\/span>i]<\/span>
          \n}<\/span><\/p>\n

          if<\/span> i ><\/span> 1<\/span> {<\/span>
          \ndp[<\/span>i]<\/span>[<\/span>1<\/span>]<\/span> =<\/span> dp[<\/span>i–<\/span>2<\/span>]<\/span>[<\/span>0<\/span>]<\/span> +<\/span> a[<\/span>i]<\/span>
          \n}<\/span>
          \n}<\/span><\/p>\n

          if<\/span> dp[<\/span>n–<\/span>1<\/span>]<\/span>[<\/span>0<\/span>]<\/span> ><\/span> dp[<\/span>n–<\/span>1<\/span>]<\/span>[<\/span>1<\/span>]<\/span> {<\/span>
          \nreturn<\/span> dp[<\/span>n–<\/span>1<\/span>]<\/span>[<\/span>0<\/span>]<\/span>
          \n}<\/span><\/p>\n

          return<\/span> dp[<\/span>n–<\/span>1<\/span>]<\/span>[<\/span>1<\/span>]<\/span>
          \n}<\/span><\/p>\n

          func<\/span> main<\/span>(<\/span>)<\/span> {<\/span>
          \nin :=<\/span> bufio.<\/span>NewReader<\/span>(<\/span>os.<\/span>Stdin)<\/span><\/p>\n

          var<\/span> n int<\/span>
          \nfmt.<\/span>Fscan<\/span>(<\/span>in,<\/span> &<\/span>n)<\/span><\/p>\n

          a :=<\/span> make<\/span>(<\/span>[<\/span>]<\/span>int<\/span>,<\/span> n)<\/span><\/p>\n

          for<\/span> i :=<\/span> 0<\/span>;<\/span> i <<\/span> n;<\/span> i++<\/span> {<\/span>
          \nfmt.<\/span>Fscan<\/span>(<\/span>in,<\/span> &<\/span>a[<\/span>i]<\/span>)<\/span>
          \n}<\/span><\/p>\n

          fmt.<\/span>Println<\/span>(<\/span>solve<\/span>(<\/span>n,<\/span> a)<\/span>)<\/span>
          \n}<\/span><\/p>\n

          C\u8bed\u8a00<\/h3>\n

          #<\/span>include<\/span> <stdio.h><\/span><\/span>
          \n#<\/span>include<\/span> <stdlib.h><\/span><\/span><\/p>\n

          \/\/ \u89e3\u51b3\u95ee\u9898<\/span>
          \nint<\/span> solve<\/span>(<\/span>int<\/span> n,<\/span> int<\/span> *<\/span>a)<\/span> {<\/span>
          \n \/\/ dp[i][0] \u4e0a\u4e00\u6b65\u8df3\u4e00\u6b65\u6700\u5927\u503c dp[i][1]\u4e0a\u4e00\u6b65\u8df3\u4e24\u6b65\u6700\u5927\u503c<\/span>
          \n int<\/span> (<\/span>*<\/span>dp)<\/span>[<\/span>2<\/span>]<\/span> =<\/span> (<\/span>int<\/span> (<\/span>*<\/span>)<\/span>[<\/span>2<\/span>]<\/span>)<\/span>calloc<\/span>(<\/span>n,<\/span> sizeof<\/span>(<\/span>int<\/span>[<\/span>2<\/span>]<\/span>)<\/span>)<\/span>;<\/span><\/p>\n

          dp[<\/span>0<\/span>]<\/span>[<\/span>0<\/span>]<\/span> =<\/span> a[<\/span>0<\/span>]<\/span>;<\/span>
          \n dp[<\/span>0<\/span>]<\/span>[<\/span>1<\/span>]<\/span> =<\/span> a[<\/span>0<\/span>]<\/span>;<\/span><\/p>\n

          for<\/span> (<\/span>int<\/span> i =<\/span> 1<\/span>;<\/span> i <<\/span> n;<\/span> i++<\/span>)<\/span> {<\/span>
          \n dp[<\/span>i]<\/span>[<\/span>0<\/span>]<\/span> =<\/span> (<\/span>dp[<\/span>i –<\/span> 1<\/span>]<\/span>[<\/span>0<\/span>]<\/span> ><\/span> dp[<\/span>i –<\/span> 1<\/span>]<\/span>[<\/span>1<\/span>]<\/span>
          \n ?<\/span> dp[<\/span>i –<\/span> 1<\/span>]<\/span>[<\/span>0<\/span>]<\/span>
          \n :<\/span> dp[<\/span>i –<\/span> 1<\/span>]<\/span>[<\/span>1<\/span>]<\/span>)<\/span> +<\/span> a[<\/span>i]<\/span>;<\/span><\/p>\n

          if<\/span> (<\/span>i ><\/span> 1<\/span>)<\/span> {<\/span>
          \n dp[<\/span>i]<\/span>[<\/span>1<\/span>]<\/span> =<\/span> dp[<\/span>i –<\/span> 2<\/span>]<\/span>[<\/span>0<\/span>]<\/span> +<\/span> a[<\/span>i]<\/span>;<\/span>
          \n }<\/span>
          \n }<\/span><\/p>\n

          int<\/span> ans =<\/span> dp[<\/span>n –<\/span> 1<\/span>]<\/span>[<\/span>0<\/span>]<\/span> ><\/span> dp[<\/span>n –<\/span> 1<\/span>]<\/span>[<\/span>1<\/span>]<\/span>
          \n ?<\/span> dp[<\/span>n –<\/span> 1<\/span>]<\/span>[<\/span>0<\/span>]<\/span>
          \n :<\/span> dp[<\/span>n –<\/span> 1<\/span>]<\/span>[<\/span>1<\/span>]<\/span>;<\/span><\/p>\n

          free<\/span>(<\/span>dp)<\/span>;<\/span><\/p>\n

          return<\/span> ans;<\/span>
          \n}<\/span><\/p>\n

          int<\/span> main<\/span>(<\/span>)<\/span> {<\/span>
          \n int<\/span> n;<\/span>
          \n scanf<\/span>(<\/span>"%d"<\/span>,<\/span> &<\/span>n)<\/span>;<\/span><\/p>\n

          int<\/span> *<\/span>a =<\/span> (<\/span>int<\/span> *<\/span>)<\/span>malloc<\/span>(<\/span>sizeof<\/span>(<\/span>int<\/span>)<\/span> *<\/span> n)<\/span>;<\/span><\/p>\n

          for<\/span> (<\/span>int<\/span> i =<\/span> 0<\/span>;<\/span> i <<\/span> n;<\/span> i++<\/span>)<\/span> {<\/span>
          \n scanf<\/span>(<\/span>"%d"<\/span>,<\/span> &<\/span>a[<\/span>i]<\/span>)<\/span>;<\/span>
          \n }<\/span><\/p>\n

          printf<\/span>(<\/span>"%d\\\\n"<\/span>,<\/span> solve<\/span>(<\/span>n,<\/span> a)<\/span>)<\/span>;<\/span><\/p>\n

          free<\/span>(<\/span>a)<\/span>;<\/span><\/p>\n

          return<\/span> 0<\/span>;<\/span>
          \n}<\/span><\/p>\n","protected":false},"excerpt":{"rendered":"

          \u5c11\u513f\u722c\u5c71\u95ef\u5173\u79ef\u5206\u6e38\u620f(Java\/Py\/C\/C\/Js\/Go)\u9898\u89e3 \u534e\u4e3aOD\u673a\u8bd5\u771f\u9898 \u65b0\u7cfb\u7edf \u534e\u4e3aOD\u4e0a\u673a\u8003\u8bd5\u771f\u9898\u65b0\u7cfb\u7edf 9\u67086\u53f7 100\u5206\u9898\u578b \u534e\u4e3aOD\u673a\u8bd5\u771f\u9898\u65b0\u7cfb\u7edf\u76ee\u5f55\u70b9\u51fb\u67e5\u770b: \u534e\u4e3aOD\u673a\u8bd5\u771f\u9898\u65b0\u7cfb\u7edf \u9898\u5e93\u76ee\u5f55｜\u673a\u8003\u9898\u5e93 \u7b97\u6cd5\u8003\u70b9\u8be6\u89e3
          \n\u9898\u76ee\u5185\u5bb9
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